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(D) $1$. The charge $+q_1$ inside the cavity induces a charge $-q_1$ on the inner surface of the cavity. Because $+q_1$ is not at the center,this indu

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Magnitude of force on charge $q_2$ due to induced charge on the inner surface of the sphere is zero.

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(D) $1$. The charge $+q_1$ inside the cavity induces a charge $-q_1$ on the inner surface of the cavity. Because $+q_1$ is not at the center,this induced charge $-q_1$ is not distributed uniformly on the inner surface.$2$. The total charge on the inner surface is $-q_1$. The electric field produced by this induced charge $-q_1$ at any point outside the sphere is equivalent to the field of a point charge $-q_1$ placed at the center of the sphere.$3$. The charge $+q_2$ is outside the sphere. The total electric field at the position of $+q_2$ is the sum of the field due to $+q_1$,the field due to the induced charge $-q_1$ on the inner surface,and the field due to the charge induced on the outer surface.$4$. However,due to electrostatic shielding,the electric field produced by the charges inside the cavity (i.e.,$+q_1$ and the induced $-q_1$ on the inner surface) at any point outside the sphere is zero. $5$. Therefore,the force on $+q_2$ due to the induced charge on the inner surface is zero.

$A$ solid conducting sphere has a cavity,as shown in the figure. $A$ charge $+q_1$ is situated away from the center. $A$ charge $+q_2$ is situated outside the sphere. Then the true statement is:

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